求极限lim(n→∞)∑(k=1→n)k^3/(n^3+n^2+n+k^3)

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求极限lim(n→∞)∑(k=1→n)k^3/(n^3+n^2+n+k^3)

求极限lim(n→∞)∑(k=1→n)k^3/(n^3+n^2+n+k^3)
求极限lim(n→∞)∑(k=1→n)k^3/(n^3+n^2+n+k^3)

求极限lim(n→∞)∑(k=1→n)k^3/(n^3+n^2+n+k^3)
k^3/(n^3+n^2+n+k^3),当k=n时,其值大于1/4,因而发散

答:
∑(k=1→)k³
=1³+2³+3³+…+n³
=n²(n+1)²/4
所以原极限
=[n²(n+1)²/4]/[n³+n²+n+n²(n+1)²/4]
=1 (同阶)请看清题目,你这解的什么乱七八糟的回复: 我...

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答:
∑(k=1→)k³
=1³+2³+3³+…+n³
=n²(n+1)²/4
所以原极限
=[n²(n+1)²/4]/[n³+n²+n+n²(n+1)²/4]
=1 (同阶)

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