已知等比数列{An},a1=3,且4a1 2a2 a3成等差数列,则a3+a4+a5等于?

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已知等比数列{An},a1=3,且4a1 2a2 a3成等差数列,则a3+a4+a5等于?

已知等比数列{An},a1=3,且4a1 2a2 a3成等差数列,则a3+a4+a5等于?
已知等比数列{An},a1=3,且4a1 2a2 a3成等差数列,则a3+a4+a5等于?

已知等比数列{An},a1=3,且4a1 2a2 a3成等差数列,则a3+a4+a5等于?
等于84

a(n) = 3q^(n-1), n = 1,2,...
4a(1) = 12,
2a(2) = 2*3q
a(3) = 3q^2.
2*2*3q = 4a(2) = 4a(1) + a(3) = 12 + 3q^2,
0 = q^2 - 4q + 4 = (q-2)^2,
q = 2.
a(n)=3*2^(n-1), n = 1,2,...
a(3)+a(4)+a(5)=3[2^2 + 2^3 + 2^4] = 12[1 + 2 + 4] = 12*7=84

由4a1,2a2,a3成等差数列,得到4a2=4a1+a3,
又a1=3,设公比为q,可化为:12q=12+3q2,即(q-2)2=0,
解得:q=2,所以an=3×2n-1,
所以a3+a4+a5=12+24+48=84.