a1+a7+a13=π,则tan(a2+a12),等差数列

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 01:41:24
a1+a7+a13=π,则tan(a2+a12),等差数列

a1+a7+a13=π,则tan(a2+a12),等差数列
a1+a7+a13=π,则tan(a2+a12),等差数列

a1+a7+a13=π,则tan(a2+a12),等差数列
a1+a7+a13=
3a7=π
a7=π/3
tan(a2+a12)
=tan(2a7)
=tan(2π/3)
=-√3

∵a1+a7+a13=3a7=π
∴a7=π/3
∴tan(a2+a12)=tan(2a7)=tan(2π/3)=tan(π-π/3)= 负根号三