1.计算 :[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]÷4(x-2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/10 23:34:51
1.计算 :[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]÷4(x-2)

1.计算 :[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]÷4(x-2)
1.计算 :[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]÷4(x-2)

1.计算 :[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]÷4(x-2)
[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]÷4(x-2)
=4(x-2)÷4(x-2)+12(x+2)(x-2)÷4(x-2)-8(x-2)(x-1)÷4(x-2)
=1+3(x+2)-2(x-1)
=1+3x+6-2x+2
=x+9

(x-2)【4+12(x+2)-8(x-1)】/ 4(x-2)
=x+9