x(t)=cos(2*pi*5*t)+cos(2*pi*10*t)+cos(2*pi*20*t)+cos(2*pi*50*t)傅立叶变换的matlab程序要求生成频谱图

Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t) 其中0 x(t)=cos(2*pi*5*t)+cos(2*pi*10*t)+cos(2*pi*20*t)+cos(2*pi*50*t)傅立叶变换的matlab程序要求生成频谱图 Matlab程序编写和出图u(x,t) = 10 + 5*cos(2*pi*t/T) + (1 + cos(2*pi*t/T))*x/5 + sum{n=1 to n=N} ( (10/pi*n [(T/2*pi) * sin(2*pi*t/T) - (25/(pi*n))^2 cos(2*pi*t/T)] * sin(pi*n*x/25) )I need it once with T=1 and once with T=365.Also for N you can 什么地方出错 x=sin(t) y=exp(-t)*cos(t) t=0:0.01:3*pi clc plot(t,x,'r-',t,y,'c--' matlab rotate程序求大神修改t=0:pi/1000:3.5*pi;k=fix(2*t/pi)+1;x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k.*cos(t);y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k.*sin(t);h=plot(x,y,'r');m=pi:pi/20:4.5*pi;n=fix(2*m/pi)-1;x0=2*cos(1.25*pi);y0=2*sin(1.25*pi);x2= matlab程序绘出一个公式的图形e^-2t * cos(3*pi*t)*[u(t)-u(t-3)] 程序如下 t=-1:0.01:4;m=(t>0);n=(t>3);x=exp(-2t)*[cos(3*pi*t)*(m-n)];plot(x,t);axis([-10,10,-2,5]);老提示 x=exp(-2t)*[cos(3*pi*t)*(m-n)];|Error:Missing MATLAB operator.公 周期信号相位频谱有这样一道题--已知周期信号f(t)=3-4sin(t+pi/4)+2cos(2t-pi/4),求其双边频谱为啥一定要化成f(t)=3-4cos(t-3pi/4)+2cos(2t-pi/4+pi),写成f(t)=3-4cos(t-3pi/4)+2cos(2t-pi/4)不行么也就是为什么一定化c MATLAB那出错了,画出来的是一条直线,m为一个值,求大神回答t=0:0.01:1;m=-((2*pi*sin((2*pi*t)/9))/9-(5*pi*sin((pi*t)/180))/18)/((2*pi*cos((2*pi*t)/9))/9-(5*pi*cos((pi*t)/180))/18);plot(t,m); matlab 中如何根据这个函数 tanx=(2(cost-cos(pi/4)*sin(t)) /(2(cost-cos(pi/4))*cos(t)+1) 画出拟合曲matlab 中如何根据这个函数 tanx=(2(cost-cos(pi/4)*sin(t)) /(2(cost-cos(pi/4))*cos(t)+1) 画出(x和t)拟合曲线 t 取值范围是 t1=input('t1=') w=50/3*pi a=2/3*pi for t=0:0.0001:t1 b=2*w*(pi-a)*t/pi c=cos(2/3*pi+b) d=sin(2/3*pit1=input('t1=')w=50/3*pia=2/3*pi for t=0:0.0001:t1b=2*w*(pi-a)*t/pic=cos(2/3*pi+b)d=sin(2/3*pi)h=cos(2/3*pi)[x,y,z]=solve('x^2+y^2+z^2=100^2+170^2','x^ 求用MATLAB编写一波形程序x=(cos(2*pi*260*t)*cos(2*pi*fc*t))+0.5*cos(2*pi*fc*t)；原函数如题,fc=20,N=1000,这是我写的 可是出不来N=1000;t=0:0.05:N-1;fc=20;x=(cos(2*pi*260*t).*cos(2*pi*fc*t))+0.5*cos(2*pi*fc*t);subplot(1,1,1);plot( matlab参数方程绘图问题t=0:pi/1000:3*pi k=fix(2*t/pi)+1; y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k*sin(t); x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k*cos(t); plot(x,y) axis equal 为什么不能运行啊, matlab中t=linspace(0,2*pi,100);x=[t;t]';y=[sin(t);cos(t)]';plot(x,y), 用MATLAB研究莫尔斯码的幅度调制与解调.本题研究莫尔斯码的幅度调制与解调.本题中信号的形式为(1)x（t)=m1(t)cos(2*pi*f1*t)+m2(t)cos(2*pi*f2*t)+m1(t)cos(2*pi*f2*t)其中信号x(t)由文件ctftmod.mat定义,可用命 这个函数的周期是?f(x)=cos[2(pi)t]+(sin10t) x=4*sin(2*pi*0.01*t).*sin(2*pi*3*t)+2*cos(pi*t*t/4);在matlab中怎样表达运行出现错误：Error using ==> mtimesInner matrix dimensions must agree. MATLAB求助,用FFT直接计算x=cos(2*pi*40*t)+2sin(2*pi*120*t)+w(t)的功率谱.用FFT直接计算x=cos(2*pi*40*t)+2sin(2*pi*120*t)+w(t)的功率谱.最好带上注释, Matlab积分报错 syms x y dx dy z t;global e a c;x=a*cos(t);y=a*e*(1-cos(t))*sin(t);dx=diff(x);dy=diff(y);z=sqrt(dx^2+dy^2);int(((a*cos(t)+c)^2+(a*e*(1-cos(t))*sin(t))^2)*z,t,0,pi-acos(c/a));报错为：Error using mupadmexError in MuPAD command:Ei