已知a、b、c、d为正实数,a>b、c>d,若b/a

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已知a、b、c、d为正实数,a>b、c>d,若b/a

已知a、b、c、d为正实数,a>b、c>d,若b/a
已知a、b、c、d为正实数,a>b、c>d,若b/a

已知a、b、c、d为正实数,a>b、c>d,若b/a
估计原题是要证明:
a/b < (b+d)/(a+c) < d/c
b/a < d/c
两边同乘以ac (a > 0,c > 0,ac > 0):
bc < ad
(b+d)/(a+c) -b/a
= [a(b+d) -b(a+c)]/[a(a+c)]
=(ab + ad - ab - bc)/[a(a+c)]
=(ad - bc) /[a(a+c)]
已知bc < ad; a > 0,c > 0,a + c > 0
故(ad - bc) /[a(a+c)] > 0
(b+d)/(a+c) -b/a > 0
(b+d)/(a+c) > b/a
d/c - (b+d)/(a+c)
=[d(a+c) -c(b+d)]/[c(a+c)]
=(ad + cd -bc -cd)/[c(a+c)]
=(ad -bc)/[c(a+c)]
已知bc < ad; a > 0,c > 0,a + c > 0
故(ad -bc)/[c(a+c)] > 0
d/c - (b+d)/(a+c) > 0
(b+d)/(a+c) < d/c

a/ba/b < b+ d/a + c < d/c ?
还是a/b < (b+ d)/(a + c) < d/c 啊