64^1/3-(-2/3)^0+log(2)8+(log(8)9)/(log(2)3)

64^1/3-(-2/3)^0+log(2)8+(log(8)9)/(log(2)3) 2^-1*64^2/3-3^log的底数3(8)+log的底数5(4)*log的底数根号2(5)+(1/cos1)^0 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 2log(5 ) 25+3log(2) 64-8log(2) 1 ( )内代表的是以什么为底 2log(5 ) 25+3log(2) 64-8log(2) 1 ( )内代表的是以什么为底 log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 2log(5)25＋3log(2)64＝? 计算：1/[log(2)3]+1/[log(5)3]=? log(3)1+log(2)根号2+lg1000 比较log(1/2)0.3,log(3)0.2的大小 计算：8^(1-log(83))(27^(2/3))-log(32) log(根号2-1)(3 求值 log【9(下标)】3+log【 9（下标）】27 log【2】（1/2）- log【1/2】2 (log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题. log(9)x+log(x^2)3=1的解为?原方程可可化为log(3 ²)x+log(x)²3=1 ,∴1/2*log(3)X+1/2*log(x)3=1,∴[log(3)x]²-2log(x)3+1=0,即[log(3)x-1]²=0请问这里的[log(3)x]²-2log(x)3+1=0是怎么推出来的,刚学基础不好, log∨6 (64)*log∨4 (1/27)*log∨3( 36) log∨6 (64)*log∨4 (1/27)*log∨3( 36) log(1/2)3,log(1/3)3,log(1/4)3比大小