x5-x4+x3-x2+x-1因式分解

来源：学生作业帮助网编辑：作业帮时间：2024/04/29 18:20:10

x5-x4+x3-x2+x-1因式分解
x5-x4+x3-x2+x-1因式分解

x5-x4+x3-x2+x-1因式分解
x5-x4+x3-x2+x-1
=x4(x-1)+x2(x-1)+(x-1)
=(x-1)(x4+x2+1)
=(x-1)(x4+2x2+1-x2)
=(x-1)[(x2+1)2-x2]
=(x-1)(x2+x-1)(x2-x+1)

原式=x4(x-1)+x²(x-1)+(x-1)
=(x-1)(x4+x²+1)
=(x-1)[(x4+2x²+1)-x²]
=(x-1)[(x²+1)²-x²]
=(x-1)(x²+x+1)(x²-x+1)

您好！
x^5-x^4+x^3-x^2+x-1
=x^4(x-1)+x^2(x-1)+x-1
=(x^4+x^2+1)(x-1)
=(x^4+2x^2+1-x^2)(x-1)
=[(x^2+1)^2-x^2](x-1)
=(x^2+1+x)(x^2+1-x)(x-1)
=(x^2+x+1)(x^2-x+1)(x-1)
希望我的答案能够帮到你~
数不胜数团队竭诚为您服务

x5-x4+x3-x2+x-1因式分解 X5-X4+X3+X2+X+1因式分解 x8+x7+x6 +x5+x4+x3+x2+x+1因式分解 x8+x7+x6+x5+x4+x3+x2+x+1因式分解因式分解X5-X4+2X3-2X2+2X-4 因式分解：x5-3x4+2x3-x2+3x-2 因式分解：x5-2x4-3x3+x2-2x-3 因式分解：x5-x4+x3-x2+x-1(数字表示几次方）因式分解：x4+x3+2x2 +x+1 分解因式X5+X4+X3+X2+X+1 因式分解 x5n+xn+1 2a2-a2b+(b-2)(ab-a)2 x5+x4+x3+x2+x+1 x4+y4-2x2y2-2x2-2y2+1 因式分解：x5+2x4-3x3-6x2+2x+4 x4+2x3+x2+1+2(x+x2)因式分解分解因式X5+X4+X3+X2+X+1X5为X的平方因式分解：x4+7x3+14x2+7x+1 x4-x3+6x2-x+15因式分解因式分解x4+x3+2x2-x+3 已知X2-X-1=0求,X5-X4-3X3+3X2+X的值