解方程:X(22-X )=96

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解方程:X(22-X )=96

解方程:X(22-X )=96
解方程:X(22-X )=96

解方程:X(22-X )=96
X(22-X )=96
x²-22x+96=0
(x-6)(x-16)=0
x=6或x=16

-x^2+22x-96=0
(x-6)(x-16)=0
所以x=6或x=16

X(22-X )=96
x^2-22x+96=0
(x-6)(x-16)=0
x-6=0,x-16=0
x=6,x=16

x(22-x)=96
x²-22x=-96
x²-22x+11²=-96+11²
(x-11)²=25
x-11=正负5x1=6,x2=16

x^2-22x+96=0…………96=-6*-16,6+16=22
(x-16)(x-6)=0…………十字相乘进行因式分解
x=16或6

X²-22X+96=0
﹙X-6﹚﹙X-16﹚=0
X=6或16

X(22-X )=96
x²-22x+96=0
(x-6)(x-16)=0
x₁=6或x₂=16

X(22-X )=96
22x-x²=96
x²-22x=-96
x²-22x+11²=-96+11²
(x-11)²=25
x-11=+/-√25
∴x1=5+11=16
x2=-5+11=6

X(22-X)=96
2X=96-22
X=37