1+(-2)+3+(-4)+5+(-6)+.+(+99)+(-100)=?

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1+(-2)+3+(-4)+5+(-6)+.+(+99)+(-100)=?

1+(-2)+3+(-4)+5+(-6)+.+(+99)+(-100)=?
1+(-2)+3+(-4)+5+(-6)+.+(+99)+(-100)=?

1+(-2)+3+(-4)+5+(-6)+.+(+99)+(-100)=?
全都抵消答案是-50

-50

-50

1-2+3-4+5-6+...+99-100
=(1-2)+(3-4)+(5-6)+...+(99-100)
=-1-1-1-1……-1
=50*(-1)=-50
1-2+3-4+5-6+...+99-100
=(1+3+5+……+99)-(2+4+6+……100)
=(1+99)*50/2-(2+100)*50/2
=50-100=-50

a1+a2,a3+a4,。。。相邻两项相加得-1,
共有50组,所以得-50.

1+(-2)=-1
3+(-4)=-1
5+(-6)=-1……
由以上得:
1+(-2)+3+(-4)+5+(-6)+.........+(+99)+(-100)
=(-1)+(-1)+(-1)+……+(-1)
=-1*50
=-50

1+(-2)=-1
3+(-4)=-1
往后依次类推,一共就有50个-1
所以就是-50

-50

-50

50个-1相加

答案正确,方法也不错~~不在补充....抓规律

1-2 = -1
3-4 = -1
……
99-100 = -1
一共50项 = -50
没注意 感谢楼下提醒。。

原式=(1-2)+(3-4)+......(99-100)
=-1-1-1-1-......-1
=-50

-50

(1+99)*50/2=2500 (2+100)*50/2=2550 2500-2550=-50 所以答案是-50

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