double x=1.52,y=5.

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double x=1.52,y=5.

double x=1.52,y=5.
double x=1.52,y=5.

double x=1.52,y=5.
double 是定义一种叫双精度数据类型的关键字
double x=1.52,y=5.2
这句话的意思就是定义变量x,y它们是双精度数据类型的变量,同时给了他们一个初始的值,x是1.52,y是5.2也就是 现在的x为1.52,y为5.2

double应该是双精度数吧。32位,4个字节。15到16个有效位

double 就是一对的意思,你用那个值除以二就是X的值了。

double x=1.52,y=5. class Point{ private double x; private double y; Point(double x1,double y1){ x=x1; y=y1; } public #includeusing namespace std;double tiaohe (double,double);int main(){double x,y;coutx>>y&&x*y!=0) {double t_tiaohe=tiaohe(x,y);cout c++习题 10.下列函数定义中正确的是( ).请解析一下每个选项.还有正确答案A.double fun(double &x,double &y) B.double fun(double &x,double &y){ {double z; return *x/*y;z=x/y; }return z;}C.double fun(double *x,double *y) D.double double pow(double x,double y) C语言#include#includeint main(){double pn[5],t[5],p0=10000;t[0]=double pow(double 1.50,double 2.0);pn[0]=p0*t[0];t[1]=double pow(double 4.10,double 8.0);pn[1]=p0*t[1];t[2]=double pow(double 4.30,double 4.0);pn[2]=p0*t[ java问题..谢谢lass Point { double x,y,z; Point(double _x,double _y,double _z) { x = _x; y = _y;class Point {double x,y,z;Point(double _x,double _y,double _z) {x = _x;y = _y;z = _z;}void setX(double _x) {x = _x;}double getDistance(Point p) {return 编程中各种符号的意思麻烦解释一下#include double x = 1.0,y = 2.0;double add( double x,double y ) {double sum;sum = x + y;}double average( double x,double y ) {double result;result = add( x,y ) / 2.0;return result;}int main( void) {doub 函数指针可以指向返回值相同但参数个数不同的函数吗?#include double f1(double x){ return x*x; }double f2(double x,double y){ return x*y; }double fun(double a,double b){//f = f2 ; r2 = (*f)(a,b);return r1 + r2;}main(){ double x1=5 class Point{ public double x,y; Point(double x,double y){ this.x=x; this.y=y; } static void show(){老是出错,感激不尽class Point{public double x,y;Point(double x,double y){this.x=x;this.y=y;}static void show(){System.out.println(x=+x+ );Sy 帮忙看看这段程序哪错了,非常感激!#include #include double f(double x) { double y;#include#includedouble f(double x){double y;y=sin(x);y=y/x;return y;}void main(){double a,b,r,h,z,n;int k,j;double p[50][50];printf(Please input'a=?,b=?,r 大大们写一下,注释啊,求class Point {double x,y,z;Point(double _x,double _y,double _z) {x = _x;y = _y;z = _z;}void setX(double _x) {x = _x;}double getDistance(Point p) {return (x - p.x)*(x - p.x) + (y - p.y)*(y - p.y) + (z - p.z)*(z - p.z);}} 以下函数用以求x的y次方 double fun(double x,int y){int i;double z=1.0;for(i=1;i double x=1.0 double y=5.0 doubledouble x=1.0 double y=5.0 double z=x––+(++y) z 的值是多少?怎么算? 英语翻译#include void main() { double x = 1,y = 2; double s = 0; for ( ; x 定义一个Point类并用成员函数 double Distance(const& Point)求两点间距离#include#includeusing namespace std;class Point{private:double X,Y;public:Point(double x,double y){X=x;Y=y;}//构造函数double GetX(){return X;}double GetY(){retu 递归二分发求方程解#include using namespace std;double f(double t){return t*t*t-3*t+4;}double b(double a,double b,int n){double t=(a+b)/2;if(n==1||f(t)==0){return t;}if(f(a)*f(t)>x>>y;cin>>c;double s=b(x,y,c);cout 类定义为什么要这样class point{public:double x,y;point(){};point(double x1,double y1){x=x1;y=y1;}//向量赋值double operator%(const point &a)//叉积{return x*a.y-y*a.x;}double operator*(const point &b)//点积{return x*b.x+y*b.y;}point ope 2.以下正确的函数定义是 .A)double fun(int x,int y) B)double fun(int x,y)所谓 { int z ; return z ;}C)fun (x,y) D)double fun (int x,int y){ int x,y ; double z ; { double z ;z=x+y ; return z ; } return z ; }