main() {int x=10,i=1,j=2; printf (“%d,%o,%x\n”,x,x,x); printf (“i=%d\n”,++i); printf (“%c\n输出结果是什么?main(){int x=10,i=1,j=2;printf (“%d,%o,%x\n”,x,x,x);printf (“i=%d\n”,++i);printf (“%c\n”,i= =j ?’E’

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/13 11:37:40
main() {int x=10,i=1,j=2; printf (“%d,%o,%x\n”,x,x,x); printf (“i=%d\n”,++i); printf (“%c\n输出结果是什么?main(){int x=10,i=1,j=2;printf (“%d,%o,%x\n”,x,x,x);printf (“i=%d\n”,++i);printf (“%c\n”,i= =j ?’E’

main() {int x=10,i=1,j=2; printf (“%d,%o,%x\n”,x,x,x); printf (“i=%d\n”,++i); printf (“%c\n输出结果是什么?main(){int x=10,i=1,j=2;printf (“%d,%o,%x\n”,x,x,x);printf (“i=%d\n”,++i);printf (“%c\n”,i= =j ?’E’
main() {int x=10,i=1,j=2; printf (“%d,%o,%x\n”,x,x,x); printf (“i=%d\n”,++i); printf (“%c\n
输出结果是什么?
main()
{int x=10,i=1,j=2;
printf (“%d,%o,%x\n”,x,x,x);
printf (“i=%d\n”,++i);
printf (“%c\n”,i= =j ?’E’: ’F’);

main() {int x=10,i=1,j=2; printf (“%d,%o,%x\n”,x,x,x); printf (“i=%d\n”,++i); printf (“%c\n输出结果是什么?main(){int x=10,i=1,j=2;printf (“%d,%o,%x\n”,x,x,x);printf (“i=%d\n”,++i);printf (“%c\n”,i= =j ?’E’
#include
int main(void)
{
int x = 10, i = 1, j = 2;
printf("%d,%o,%x\n", x, x, x); //%d,%o,%x分别对应输出为十进制,八进制,十六进制
printf("i=%d\n", ++ i);
/*
++i与i++的区别为i++为参与运算后加一,而++i先加一后运算
例如
i=5;
printf("%d",i++);
你既然知道i++是先取值那么,printf这个函数当然取的是i=5的时候的值咯.
相反的
i=5;
printf("%d",++i)
则是先自加后,再把i的值取出来,printf所取的i值当然就是6咯
*/
printf("%c\n", j); //输出j所对应的ASCII码所对应的字符
}
输出为:
10,12,a
i=2
\x02

main(){int x,i;for(i=1;i C语言问题int x=3;incre();main(){ int i; for (i=1;i int x=3;main(){int i;for(i=1;i int x=3;main(){int i;for(i=1;i main(){ int i=1;while (i main() {int i; for(i=1;i main() { int i=1,s=0; for(i #define MAX 10 int a[MAX],i; int main( ) sub1( ) { for(i=0;i #include void main() { int i;int sum=0; for(i=1;i 我想搞个X的Y次方的 算法 #include stdafx.hint main(int argc,char* argv[]){int pow(int x,int y);int a,b,c;scanf(%f,%f,&a,&b);c=pow(a,b);printf(%f ,c);return 0;}int pow(int x,int y){int i,z;i=1;z=x;while(i main() {int x=10,i=1,j=2; printf (“%d,%o,%x ”,x,x,x); printf (“i=%d ”,++i); printf (“%c 输出结果是什么?main(){int x=10,i=1,j=2;printf (“%d,%o,%x ”,x,x,x);printf (“i=%d ”,++i);printf (“%c ”,i= =j ?’E’ main(){ int x=5; while(x #define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i--)a[i+1]=a[i]; return m; } void main() #define N 20fun(int a[],int n,int m){int i;for(i=m;i>n;i--)a[i+1]=a[i];return m;}void main(){ int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,0,N/2);for(i=0;i 求高手解释一下这段程序#include class Test {int x,y; public: Test(int i,int j=0) {x=i;y=j;} int get(int i,int j) {return i+j;} }; void main() {Test t1(2),t2(4,6); int (Test::*p)(int,int=10); p=Test::get; cout int f() { static int i=0; int s=1; s+=i; i++; return s; }main() { int i,a=0; for(i=0;i 一道c++的题目,就是不知道为什么算不对,快被逼疯了……#include using namespace std;int main(){int sort(int a[10]);int insert(int a[10],int b);int x[10],i,j,y,z[11];for(i=0;i>x[i];x[10]=sort(x);for(i=0;i #include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}#include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8},i;for(i=2;i c语言求出 2 到 m 之间 素数#include int main (){int i,m,x=1,j;scanf(%d,&m);for(i=3;i