(i?a[i-1]!='\n':1)

(i?a[i-1]!=' ':1) t=a[i]; a[i]=a[n-i-1];a[n-i-1]=t; 1、在资金时间价值计算时,i和n给定,下列等式中正确的有?为什么?1、A (F/A,i,n)=[(P/F,i,n)(A/P,i,n)]-1B (A/P,i,n)=(A/F,i,n)+iC (F/P,i,n)=(A/P,i,n)/(F/A,i,n)D(A/P,i,n)(F/A,i,n)=(P/F,i,n) #define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i--)a[i+1]=a[i]; return m; } void main() #define N 20fun(int a[],int n,int m){int i;for(i=m;i>n;i--)a[i+1]=a[i];return m;}void main(){ int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,0,N/2);for(i=0;i 技术经济学证明题,(P/A,i,n)=（P/A,i,n-1）+（P/F,i,n） a(n+2)=(2+i^2n)an+1+i^2n,求an 关于lingo程序的,sets:A/1..4/:c,b,n;X/A,A/:D;endsetsmin=1.1*n(1)+1.2*n(2)+1.3*n(3)+1.4*n(4);@for(A(i):@sum(A(j):c(i)*D(i,j)=1750);@for(A(i):@sum(A(j):n(i)*D(i,j)=b(i));@for(A(i):@gin(n(i)));@for(A(j):@for(A(i):@gin(D(i,j))));n(1)>n(2);n(2)>n(3);n 工程经济学课后证明题1,（P/F,i,n+2）+(P/A,i,n+1)=(P/A,i,n+2)2.(A/P,i,n+1) - （A/F,i,n+1）=i ( F/A,n,i)= (F/A,n+1,i)-1这个公式怎么计算 若limXn=a,a不等于0,证明存在N>0,当n>N时,有1/ I Xn I < 2/ I a II I表示绝对值 lingo错误分析：csets:a/23..46/:m,n; endsets @sum(a(i):n(i))=4;sets:a/23..46/:m,n;endsets@sum(a(i):n(i))=4;@sum(a(i):m(i))=5;@sum(a(i):m(i)*n(i)*(3+(i-1)*0.5)=89;@for(a(i):@gin(m(i)));@for(a(i):@bin(n(i)));end错误1017请帮忙分析错误 在资金时间价值计算时,i和n给定,下列等式中正确的有( ).A．(F/A,i,n)=[(P/F,i,n)(A/p,i,n)]－1 （是最后是负1次方） B．(A/P,i,n)=(A/F,i,n)+i C．(A/F,i,n)=(A/P,i,n)-i D．(F/P,i,n)=(A/P,i,n)/(F/A,i,n) E．(A/P,i,n)(F/A,i,n) 求I n=∫1 /(x ^2+a^2)^n dx,其中n为正整数(I n为数列I的第n项). A=12*n*a*i(1+i)^(12*n)/((1+i)^(12*n)-1);B=a+2*i*((6*n*a-(3*n-1)(12*n-1));当1 数列不等式题.已知a[i]>=i,(i=1,2,...,n),a[i]+a[2]+.+a[n}>=[n(n+1)^2]/2.求证：∑i=1 to n（a[i]-i)/(i+∑j≠i a[j])图片我发到我的百度空间那。http://hi.baidu.com/%CA%FD%D1%A7lover/album/item/6ec8d0126f98738aac6e75ce.html# 1+i^n+i^2n+...+i^2000n＝? main() { int a,b,i,min,n; scanf(%d%d,&a,&b); min=a; if(b/a!=n&&n>1) { for(i=min/2;i>0;i--) if(a%i请问怎么求这两个数的最大公约数 a1){for(i=min/2;i>0;i--)if(a%i==0&&b%i==0) break;}else if(b/a==n&&n>1)i=a;printf(%d ,i);}程序应该 (1+i)^2n/1-i+(1-i)^2n/1+i=2^n,求最小正整数n?