lim(2^x/1次幂-1)/(2^x/1次幂+1)

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lim(2^x/1次幂-1)/(2^x/1次幂+1)

lim(2^x/1次幂-1)/(2^x/1次幂+1)
lim(2^x/1次幂-1)/(2^x/1次幂+1)

lim(2^x/1次幂-1)/(2^x/1次幂+1)
lim(x→0)[(2^x-1)/(2^x+1)]
=lim(x→0)(2^x-1)/[lim(x→0)(2^x+1)]
=(2^0-1)/(2^0+1)
=(1-1)/(1+1)
=0

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