(Y-X)^3(X-Y)^m+(X-Y) ^m+1(Y-X)^2

来源：学生作业帮助网编辑：作业帮时间：2024/04/28 04:54:50

(Y-X)^3*(X-Y)^m+(X-Y) ^m+1*(Y-X)^2
(Y-X)^3*(X-Y)^m+(X-Y) ^m+1*(Y-X)^2

(Y-X)^3*(X-Y)^m+(X-Y) ^m+1*(Y-X)^2
原式=（Y-X)^3(X-Y)^m+(X-Y)^m*（X-Y)(Y-X)²
=(Y-X)^3(X-Y)^m+(X-Y)^m*(-(Y-X)^3)
=(Y-X)^3(X-Y)^m-(X-Y)^m(Y-X)^3
=0

(y-x)^3 * (x-y)^m+(x-y)^(m+1)*(y-x)^2
=-(x-y)^3*(x-y)^m+(x-y)^(m+1)*(x-y)^2
=-(x-y)^(m+3)+(x-y)^(m+3)
=0
刚看错了，现在改了
希望我的回答对你有帮助，采纳吧O(∩_∩)O！

(y-x)^3 * (x-y)^m+(x-y)^m+1*(y-x)^2
=（Y-X)^3(X-Y)^m+(X-Y)^m*（X-Y)(Y-X)²
=(Y-X)^3(X-Y)^m+(X-Y)^m*(-(Y-X)^3)
=(Y-X)^3(X-Y)^m-(X-Y)^m(Y-X)^3
=0

这不是初一的数学题！初一是建在小学的基础上绝大部分初中内容在初二我今年刚初三毕业是初一的题目的话这道题我怎么可能不会！不过计算机上面显示答案是0

计算：(y-x)^3(x-y)^m-(x-y)^m+2(y-x) (Y-X)^3*(X-Y)^m+(X-Y) ^m+1*(Y-X)^2 3（x-1)³y-（1-x）³z m(x-y)²-x+y x²(x+y)(y-x)-xy(x+y)(x-y) 因式分解 (3x-y)(3y+x)-(x-y)(x+y) 4m(x-y)-2m^2(y-x)^3 ：x（x-y）-y（y-x） m（x-y）²-x+y m(x-y)的平方-x+y m(x-y)-n(y-x)因式分解 m（x-y）平方-x+y m(x-y)+n(y-x) 设M={(x,y)||x|+|y| x^n*y*(-x^2y^m) m(x+y)+n(x+y)-x-y因式分解因式分解方法:m(x-y)(x-y)-x+y 已知x>y,m {(x,y) |x|+|y| x>y?x:y 分解因式：(x+y)(x-y)-(x+y)² 3m(m-n)+6n(n-m) x(x-y)-y(y-x) (x-3)²+（3x-9)(x+y)(x-y)-(x+y)² 3m(m-n)+6n(n-m) x(x-y)-y(y-x) (x-3)²+（3x-9)