帮解下数学题(初二)写过程哦 谢了若X/2=Y/3=Z/5,则(2X-3Y+Z)/(2Y-3X+Z)=__________.

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帮解下数学题(初二)写过程哦 谢了若X/2=Y/3=Z/5,则(2X-3Y+Z)/(2Y-3X+Z)=__________.

帮解下数学题(初二)写过程哦 谢了若X/2=Y/3=Z/5,则(2X-3Y+Z)/(2Y-3X+Z)=__________.
帮解下数学题(初二)写过程哦 谢了
若X/2=Y/3=Z/5,则(2X-3Y+Z)/(2Y-3X+Z)=__________.

帮解下数学题(初二)写过程哦 谢了若X/2=Y/3=Z/5,则(2X-3Y+Z)/(2Y-3X+Z)=__________.
设x/2=y/3=z/5=k
所以x=2k,y=3k,z=5k
带入到式子中(2k-9k+5k)/(6k-6k+5k)=-2/5k

x:y:z=2:3:5
(2X-3Y+Z)/(2Y-3X+Z)=(2*2-3*3+5):(2*3-3*2+5)=0

X/2=Y/3=Z/5得:x=2y/3;z=5y/3得(2X-3Y+Z)/(2Y-3X+Z)=(2y/3-3y+5y/3)/(2y-2y/3+5y/3)= 自己算

设x/2=y/3=z/5=k x=2k y=3k z=5k
2x-3y+z=4k-9k+5k=0
所以原式=0

一楼的,题目没说等于1呀
设X=2a,Y=3a,Z=4a(a不为0)
所以原式等于(2*2-3*3+5)a:(2*3-3*2+5)a=0