先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2

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先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2

先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2
先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2

先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2
.(1/a-b-1/a+b)÷b/a2-2ab+b2
=(a+b-a+b)/(a-b)(a+b)÷b/(a-b)²
=2b/(a+b)÷b/(a-b)
=2(a-b)/(a+b)
=2(1+√2-1+√2)/(1+√2+1-√2)
=2x2√2/2
=2√2
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