作业帮化简（x-1/x+1)-（x+1/x+2)除以x+3/x*+4x+4*是平方
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化简（x-1/x+1)-（x+1/x+2)除以x+3/x*+4x+4*是平方
化简（x-1/x+1)-（x+1/x+2)除以x+3/x*+4x+4
*是平方
化简（x-1/x+1)-（x+1/x+2)除以x+3/x*+4x+4*是平方
[(X-1)/(X+1)-(X+1)/(X+2)]/[(X+3)/(X+2)^2]
={(X^2+X-2)-(X^2+2X+1)/(X+1)(X+2)}/[(X+3)/(X+2)^2]
=[-(X+3)/(X+1)(X+2)]*[(X+2)^2/(X+3)]
=-(X+2)/(X+1)
=[-(x+3)/(x+1)(x+2)]*(x+2)^2/(x+3)
=-(x+2)/(x+1)