2x+3y+19=0 x+5y-1=0怎么解

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2x+3y+19=0 x+5y-1=0怎么解

2x+3y+19=0 x+5y-1=0怎么解
2x+3y+19=0 x+5y-1=0怎么解

2x+3y+19=0 x+5y-1=0怎么解
x+5y-1=0
x=-5y+1
代入2x+3y+19=0
-10y+2+3y+19=0
7y=21
所以
y=3
x=-5y+1=-14


{2x+3y=-19①
{x+5y=1②
由②×2-①,得7y=21
y=3
将y=3代入②,得x+15=1
x=-14
∴原方程组的解为
{x=-14
{y=3

(1)2x+3y+19=0
(2)x+5y-1=0
(1)-2*(2)后,消去x
-7y+21=0
所以y=3
代入(1)得,x=-14

x+5y-1=0 ==> x = 1-5y
2x+3y+19=0 ==> 2(1-5y)+3y+19=0 ==> y=3, x=1-5*3=-14
x=-14
y=3

你上几年级了?
x=-14,y=3

因为x+5y-1=0,所以x=-5y+1,把这式子代入2x+3y+19=0,得 2(-5y+1)+3y+19=0,算出y=3,再把y=3代入x=-5y+1,得 x=-14

解方程组吧?
把第二个式子的写成x=1-5y,代入第一个式子。
即:2(1-5y)+3y+19=0解出y=3
所以:x=1-3*5=-14
即 x=-14
y=3

加减法
2x+3y+19=0 (1)
x+5y-1=0 (2)
(2)*2-(1),可得y (3)
把(3)代入(1),解出x,行了,你试试!

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