若0若0
若0令f(x)=x^2(1-2x)=-2x^3+x^2∵f′(x)=-6x^2+2x令f′(x)=-6x^2+2x=0x=0或1/3∴x=0或1/3为f(x)极值点又∵0<x<1/2∴maxf(x)={f(0),f(1/3),f(1/2)}=f(1/3)=1/27